How this calculation works
Reduce the exponent before inspecting the denominator. For example, 2/6 is 1/3 and has a real value on negative bases.
Reduce p/q, then take the qth root and raise to pA worked example
(−8)^(2/3) = (−2)² = 4.
Good to know
Negative bases require an odd denominator after reduction.
Reference: OpenStax Algebra and Trigonometry (opens in a new tab) ↗
Read the result
Evaluate a rational power and check whether a negative base has a real result.
The primary result is labeled “Real value”. Keep the input definitions in view when comparing this result with another method.
Try a related calculation
Negative bases require an odd denominator after reduction.
For a related exercise, try the quadratic equation solver.
A few questions, answered
How can I check the default inputs by hand?
(−8)^(2/3) = (−2)² = 4.
Which rule does this calculator apply?
Reduce p/q, then take the qth root and raise to p