Maths & numbers

Mean value theorem point for a quadratic calculator

Find the point where the tangent slope equals the interval’s secant slope.

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Behind the numbers

How this calculation works

Find the point where the tangent slope equals the interval’s secant slope.

THE FORMULAFor a nonconstant derivative of a quadratic, c=(left+right)/2

A worked example

On [2,6], the point is x=4.

Good to know

A linear function has the same slope throughout the interval.

Read the result

Find the point where the tangent slope equals the interval’s secant slope.

The primary result is labeled “Mean value theorem x”. Keep the input definitions in view when comparing this result with another method.

Try a related calculation

A linear function has the same slope throughout the interval.

For a related exercise, try the quadratic equation solver.

A few questions, answered

How can I check the default inputs by hand?

On [2,6], the point is x=4.

Which rule does this calculator apply?

For a nonconstant derivative of a quadratic, c=(left+right)/2

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