Maths & numbers

Integer partitions into distinct parts calculator

Count unordered sums using each positive part at most once.

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Behind the numbers

How this calculation works

Count unordered sums using each positive part at most once.

THE FORMULAMultiply factors (1+xᵏ) through k=n and read the coefficient of xⁿ

A worked example

Six has four such sums: 6, 5+1, 4+2 and 3+2+1.

Good to know

Zero has one empty partition.

Read the result

Count unordered sums using each positive part at most once.

The primary result is labeled “Partitions”. Keep the input definitions in view when comparing this result with another method.

Try a related calculation

Zero has one empty partition.

For a related exercise, try the greatest common divisor.

A few questions, answered

How can I check the default inputs by hand?

Six has four such sums: 6, 5+1, 4+2 and 3+2+1.

Which rule does this calculator apply?

Multiply factors (1+xᵏ) through k=n and read the coefficient of xⁿ

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