How this calculation works
Solve a linear fractional equation and preserve the denominator restriction.
(ax+b)/(cx+d)=k implies (a−kc)x=kd−b on the original domainA worked example
(2x+3)/(x−1)=4 gives x=3.5, which is allowed because x≠1.
Good to know
A denominator that vanishes identically has empty domain.
Reference: OpenStax Algebra and Trigonometry (opens in a new tab) ↗
Read the result
Solve a linear fractional equation and preserve the denominator restriction.
The primary result is labeled “Solution x”. Keep the input definitions in view when comparing this result with another method.
Try a related calculation
A denominator that vanishes identically has empty domain.
For a related exercise, try the quadratic equation solver.
A few questions, answered
How can I check the default inputs by hand?
(2x+3)/(x−1)=4 gives x=3.5, which is allowed because x≠1.
Which rule does this calculator apply?
(ax+b)/(cx+d)=k implies (a−kc)x=kd−b on the original domain