Statistics & probability

Spearman rank correlation with ties calculator

Preserve pairing and use average tied ranks to describe monotonic association.

Your numbers

1–1,000 finite values within ±1 trillion, separated by commas, spaces or semicolons. Nonzero magnitudes must be at least 10⁻¹². Keep paired lists in corresponding row order; no missing-value markers.
1–1,000 finite values within ±1 trillion, separated by commas, spaces or semicolons. Nonzero magnitudes must be at least 10⁻¹². Keep paired lists in corresponding row order; no missing-value markers.

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Your result

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Enter your numbers and select Calculate.

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Explore the result

Preserve paired rows and retain equal-value ties.

Worked example comparison
ExampleOutputWhat to notice
Average tied ranksSpearman rank correlation ρ0.948683The default coefficient is √0.9, about 0.948683.
Matching tied ordersSpearman rank correlation ρ1Both variables have matching average ranks, giving +1.
Reversed tied ordersSpearman rank correlation ρ-1The second average ranks reverse the first, giving −1.

Check your understanding

Can the no-ties shortcut always be used here?

No. Correlate the average-rank lists to retain ties correctly.

Does coefficient +1 prove a straight line in original units?

No. Strictly increasing nonlinear transformations can preserve ranks.

Behind the numbers

How this calculation works

Rank each variable separately in ascending order, assign tied entries the average of their occupied ranks and correlate the resulting paired ranks. Constant lists have no defined rank correlation.

THE FORMULAρ = Pearson correlation of the two average-rank lists

A worked example

For first values 1,2,2,4, the ranks are 1,2.5,2.5,4. Second values 10,20,30,40 rank 1,2,3,4. Their rank correlation is approximately 0.948683.

Good to know

At least two paired observations and variation in each list. No significance test, p-value, causal interpretation or missing-value deletion. Equal numeric values tie; nearly equal values are not merged.

Rank each variable without breaking the pairs

The tool ranks each list separately but attaches the ranks back to the original pair positions. In 1,2,2,4, the two equal values occupy ascending positions two and three, so each receives rank 2.5. The ranked list is 1,2.5,2.5,4.

Paired with 10,20,30,40, whose ranks are 1,2,3,4, the result is approximately 0.948683. Sorting the two raw lists independently before entering them would change the question and could manufacture an increasing association that was absent in the original paired data.

The percentile rank calculator evaluates one target against a reference list. Spearman correlation instead compares two paired rank patterns.

Ties require the full correlation of ranks

The implementation centers both rank lists and divides their cross-product sum by the product of their centered lengths. This directly calculates the Pearson correlation of average ranks. It does not apply the familiar no-ties squared-rank-difference shortcut to tied data.

Identical varying rank lists give +1, and exactly reversed varying ranks give −1. A constant list gives the same rank to every observation, leaving zero variation in that denominator. The calculator identifies the constant field instead of returning a misleading zero association.

A monotonic association is not a fitted straight line

A strictly increasing nonlinear transformation preserves rank order. For example, replacing positive measurements by their cubes can leave Spearman correlation unchanged even though the numerical distances grow very differently. Rank association describes order, not a slope in the original units.

The simple linear regression calculator works with original numeric distances and estimates a straight-line prediction under its own assumptions. The percentile rank calculator answers where one target lies within a reference list. This page supplies neither a regression line nor a p-value or causal claim.

A few questions, answered

Are nearly equal numbers treated as ties?

Only values equal after numeric parsing tie. No rounding or tolerance-based merging is applied.

Can the result be used as a significance test?

This page reports no p-value, null distribution or test decision.

Why is a constant list rejected?

Its ranks have zero variance, making the correlation denominator zero.

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