How this calculation works
An exchanger can be rated from inlet temperatures, stream heat-capacity rates and overall conductance without first knowing outlet temperatures. The effectiveness–NTU method predicts those outlets under a stated ideal flow arrangement. This page compares single-pass counterflow and parallel flow with constant capacity rates. It also reports the logarithmic mean temperature approach equivalent to the predicted heat transfer and entered UA.
NTU=UA/Cmin; Q=effectiveness Cmin(Th,in−Tc,in); equivalent LMTD=Q/UAA worked example
For inlet temperatures one hundred and twenty degrees, equal capacity rates one hundred watts per kelvin and UA one hundred, counterflow NTU is one and effectiveness is one half. Heat transfer is four thousand watts and both outlet temperatures are sixty degrees. The equal-capacity counterflow case uses its analytical limiting expression instead of dividing by a vanishing capacity-ratio difference.
Good to know
The reported mean approach is Q divided by UA; at zero UA its limiting inlet approach is shown while heat transfer is zero. This avoids reporting an undefined zero-over-zero result as a measured driving difference. Multipass shell geometry, fouling, heat loss to surroundings and pressure drop are excluded. The calculation is an ideal rating comparison rather than approval of a specific exchanger or operating condition.
Reference: NPTEL — heat exchanger effectiveness and NTU (opens in a new tab) ↗
What this calculation answers
An exchanger can be rated from inlet temperatures, stream heat-capacity rates and overall conductance without first knowing outlet temperatures. The effectiveness–NTU method predicts those outlets under a stated ideal flow arrangement.
This page compares single-pass counterflow and parallel flow with constant capacity rates. It also reports the logarithmic mean temperature approach equivalent to the predicted heat transfer and entered UA.
The Heat energy calculator relates an amount of heat to temperature change. Exchanger rating additionally needs two flowing capacity rates, conductance and stream arrangement.
Use the right input conventions
Heat-capacity rate is mass flow times specific heat, in watts per kelvin; it is not specific heat alone. UA is overall heat-transfer coefficient times area in the same watts-per-kelvin unit.
Enter hot inlet above cold inlet and use positive stream capacity rates. Both streams exchange sensible heat only, so condensation, evaporation and strongly changing specific heat are outside the model.
Interpret the result
Effectiveness is heat transfer divided by the maximum possible value based on the smaller capacity rate and inlet temperature gap. NTU is conductance divided by that smaller capacity rate.
Hot outlet follows its heat loss and cold outlet follows the same heat gain. Counterflow permits a cold outlet above the hot outlet without violating local temperature ordering because the two outlets are at opposite physical ends.
Work through the example
For inlet temperatures one hundred and twenty degrees, equal capacity rates one hundred watts per kelvin and UA one hundred, counterflow NTU is one and effectiveness is one half.
Heat transfer is four thousand watts and both outlet temperatures are sixty degrees. The equal-capacity counterflow case uses its analytical limiting expression instead of dividing by a vanishing capacity-ratio difference.
Where the model stops
The reported mean approach is Q divided by UA; at zero UA its limiting inlet approach is shown while heat transfer is zero. This avoids reporting an undefined zero-over-zero result as a measured driving difference.
Multipass shell geometry, fouling, heat loss to surroundings and pressure drop are excluded. The calculation is an ideal rating comparison rather than approval of a specific exchanger or operating condition.
A few questions, answered
Can counterflow cold outlet exceed hot outlet?
Yes, because those outlets occur at opposite ends. The model still respects the local thermal driving differences.
What changes in the comparison?
Keep conductance and capacities fixed but switch arrangement; parallel-flow effectiveness is lower for this example.