How this calculation works
Find the length from a vertex to an arbitrary point on its opposite side.
d²=(b²n+c²m)/(m+n)−mn when b adjoins m and c adjoins nA worked example
With sides 5 and 5 and base parts 2 and 4, the square of the cevian is 25−8=17.
Good to know
The base is the sum of the two entered segments.
Reference: OpenStax Algebra and Trigonometry, Trigonometric Applications (opens in a new tab) ↗
Read the result
Find the length from a vertex to an arbitrary point on its opposite side.
The primary result is labeled “Cevian length”. Keep the input definitions in view when comparing this result with another method.
Try a related calculation
The base is the sum of the two entered segments.
For a related exercise, try the circle calculator.
A few questions, answered
How can I check the default inputs by hand?
With sides 5 and 5 and base parts 2 and 4, the square of the cevian is 25−8=17.
Which rule does this calculator apply?
d²=(b²n+c²m)/(m+n)−mn when b adjoins m and c adjoins n