How this calculation works
Percent impedance values refer to a selected transformer rating. Combining resistance from one base with reactance from another does not describe one coherent equivalent circuit. Enter both components on the same apparent-power and voltage base.
Approximate regulation % = load fraction × [R% × PF ± X% × √(1 − PF²)]; copper loss = rated VA × R%/100 × load fraction²A worked example
With 1 percent resistance, 4 percent reactance, full load and 0.8 lagging PF, first-order regulation is 3.2 percent. The corresponding voltage-drop term at 400 V is 12.8 V.
Good to know
First-order R/X percent approximation with load-current fraction. No exact terminal phasors, core loss, saturation, temperature, taps, efficiency guarantee or parallel sharing assessment.
Reference: NPTEL — transformer voltage regulation (opens in a new tab) ↗
Use resistance and reactance on the same base
Percent impedance values refer to a selected transformer rating. Combining resistance from one base with reactance from another does not describe one coherent equivalent circuit. Enter both components on the same apparent-power and voltage base.
The magnitude of impedance is the square root of the sum of their squares. That magnitude alone is not the same as the approximate voltage regulation, which also depends on the phase relationship of current and voltage.
The Three phase star delta balanced load calculator checks line and phase quantities for an ideal balanced load. Apply a compatible transformer base and load convention before using those quantities in a regulation estimate.
Leading current can reverse the reactive term
The first-order expression adds the reactance term for lagging power factor and subtracts it for leading power factor. Negative calculated regulation is therefore retained rather than forced to zero. It indicates a voltage-rise tendency in this approximation.
Load is expressed as a fraction of rated current. The voltage-drop term scales linearly with that fraction, while the resistive copper-loss estimate scales with its square. Doubling load in this model therefore quadruples that loss term.
Do not confuse a local approximation with a terminal solution
The percentage expression is a first-order engineering approximation. It does not solve the full circuit phasors at a specified output load or account for saturation, temperature changes and taps. The displayed voltage is a drop term, not a guaranteed measured terminal value.
The loss estimate includes winding resistance but no core loss. It is not an efficiency calculation. Equipment approval, thermal loading and parallel-transformer sharing need their own data and analysis.
Work through the example
With 1 percent resistance, 4 percent reactance, full load and 0.8 lagging PF, first-order regulation is 3.2 percent. The corresponding voltage-drop term at 400 V is 12.8 V.
Use the worked table to trace where each input enters. Then change one assumption and calculate again, leaving the others fixed. A comparison is easier to interpret when the change has one identifiable cause rather than a different set of measurements, dates and rates all at once.
What this model does not establish
First-order R/X percent approximation with load-current fraction. No exact terminal phasors, core loss, saturation, temperature, taps, efficiency guarantee or parallel sharing assessment.
Keep the input assumptions with any exported result. Illustrative values do not become observations merely because the output is precise. For a real purchase, financial reconciliation or technical decision, check the underlying records and applicable requirements before treating this scenario as a final answer.
A few questions, answered
What formula does the calculator use?
Approximate regulation % = load fraction × [R% × PF ± X% × √(1 − PF²)]; copper loss = rated VA × R%/100 × load fraction²
What should I verify before using this result?
First-order R/X percent approximation with load-current fraction. No exact terminal phasors, core loss, saturation, temperature, taps, efficiency guarantee or parallel sharing assessment.
Are the example inputs live records?
No. They are an illustrative calculation case. Replace them with records and measurements appropriate to your situation.