High School Synthetic Division Calculator
Divide polynomials by linear binomials (x – c) instantly.
Space separated, highest degree first. (e.g., “1 -5 6” for x²-5x+6)
For divisor (x – c), enter c. For (x + 3), enter -3.
Result Quotient & Remainder
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Synthetic Tableau
Remainder Theorem Graph
Understanding the Synthetic Division Calculator
Synthetic Division is a shortcut method for dividing a polynomial by a linear factor of the form (x – c). It is significantly faster and uses less space than traditional polynomial long division. However, it requires careful setup, particularly ensuring that all coefficients are represented (including zeros for missing terms) and that the divisor is in the correct format.
How the Process Works
The method involves a tableau (a grid). 1. First, you list the coefficients of the dividend. 2. You calculate the root of the divisor c. 3. You “bring down” the leading coefficient. 4. Then, you multiply this value by c, place the result in the next column, add the column, and repeat. The final number in the bottom row is the Remainder, and the preceding numbers are the coefficients of the Quotient polynomial.
Why use a Synthetic Division Calculator?
While manual calculation is a great skill, it is prone to arithmetic errors, especially with signs. This tool automates the process, providing immediate feedback. It is especially useful when applying the Rational Root Theorem, where you might need to test many potential roots rapidly to factor a high-degree polynomial.
Connection to the Remainder Theorem
One of the most powerful applications of synthetic division is evaluating functions. The Remainder Theorem states that if you divide a polynomial P(x) by (x – c), the remainder is equal to P(c). Our visual graph demonstrates this by plotting the function and highlighting exactly where x = c.
FAQ
Yes, this tool is completely free and open-source for educational use.
Synthetic division works best for monic linear divisors (x – c). For (2x – 1), rewrite it as 2(x – 1/2). Divide by (x – 1/2) using c=0.5, then divide the resulting quotient coefficients by 2.
If the remainder is 0, then (x – c) is a perfect factor of the polynomial, and c is a root (x-intercept) of the graph.
Yes! If you have x³ + 1, enter “1 0 0 1”. Missing coefficients will lead to incorrect answers.